1. Basic Formulas
Table of Content
- Pressure Gradient
- Hydrostatic Pressure
- Converting Pressure into Mud Weight
- Specific Gravity
- Equivalent Circulation Density
- Maximum Allowable Mud Weight
- Pump Output
- Annular Velocity
- Capacity Formulas
- Control Drilling
- Buoyancy Factor
- Hydrostatic Pressure Decrease POOH
- Loss of Overbalance Due to Falling Mud Level
- Formation Temperature
- Hydraulic Horsepower
- Drill Pipe, Drill Collar Calculation
- Pump Pressure, Pump Strokes
- Cost Per Foot
- Temperature Conversion Formulas
1.16 Drill Pipe/Drill Collar Calculations
Capacities, bbl/ft, displacement, bbl/ft, and weight, lb/ft, can be calculated from the following formulas:
Weight, lb/ft = displacement, bbl/ft × 2747 lb/bbl
Example: Determine the capacity, bbl/ft, displacement, bbl/ft,
and weight, lb/ft, for the following:
Drill collar OD = 8.0 in.
Drill collar ID = 2-13/16 in.
Convert 13/16 to decimal equivalent: 13 ÷ 16 = 0.8125
Capacity = 0.007684 bbl/ft
Displacement = 0.0544879 bbl/ft
Weight, lb/ft = 0.0544879 bbl/ft × 2747 lb/bbl
Weight = 149.678 lb/ft
Rule of thumb formulas
Weight, lb/ft, for REGULAR DRILL COLLARS can be approximated by the following formula:
Weight, lb/ft = (OD, in.2 − ID, in.2) × 2.66
Example: Regular drill collars Drill collar OD = 8.0 in.
Drill collar ID = 2-13/16 in.
Decimal equivalent = 2.8125 in.
Weight, lb/ft = (8.02 − 2.81252) ×
2.66
Weight, lb/ft = 56.089844 × 2.66
Weight = 149.19898 lb/ft
Weight, lb/ft, for SPIRAL DRILL COLLARS can be approximated by the following formula:
Weight, lb/ft = (OD, in.2 − ID, in.2) × 2.56
Example: Spiral drill collars Drill collar OD = 8.0 in.
Drill collar ID = 2-13/16 in.
Decimal equivalent = 2.8 125 in.
Weight, lb/ft = (8.02 − 2.81252) ×
2.56
Weight, lb/ft = 56.089844 × 2.56
Weight = 143.59 lb/ft